Integrand size = 17, antiderivative size = 79 \[ \int \frac {\sec ^2\left (a+b \log \left (c x^n\right )\right )}{x^3} \, dx=-\frac {2 e^{2 i a} \left (c x^n\right )^{2 i b} \operatorname {Hypergeometric2F1}\left (2,1+\frac {i}{b n},2+\frac {i}{b n},-e^{2 i a} \left (c x^n\right )^{2 i b}\right )}{(1-i b n) x^2} \]
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Time = 0.08 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.176, Rules used = {4605, 4601, 371} \[ \int \frac {\sec ^2\left (a+b \log \left (c x^n\right )\right )}{x^3} \, dx=-\frac {2 e^{2 i a} \left (c x^n\right )^{2 i b} \operatorname {Hypergeometric2F1}\left (2,1+\frac {i}{b n},2+\frac {i}{b n},-e^{2 i a} \left (c x^n\right )^{2 i b}\right )}{x^2 (1-i b n)} \]
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Rule 371
Rule 4601
Rule 4605
Rubi steps \begin{align*} \text {integral}& = \frac {\left (c x^n\right )^{2/n} \text {Subst}\left (\int x^{-1-\frac {2}{n}} \sec ^2(a+b \log (x)) \, dx,x,c x^n\right )}{n x^2} \\ & = \frac {\left (4 e^{2 i a} \left (c x^n\right )^{2/n}\right ) \text {Subst}\left (\int \frac {x^{-1+2 i b-\frac {2}{n}}}{\left (1+e^{2 i a} x^{2 i b}\right )^2} \, dx,x,c x^n\right )}{n x^2} \\ & = -\frac {2 e^{2 i a} \left (c x^n\right )^{2 i b} \operatorname {Hypergeometric2F1}\left (2,1+\frac {i}{b n},2+\frac {i}{b n},-e^{2 i a} \left (c x^n\right )^{2 i b}\right )}{(1-i b n) x^2} \\ \end{align*}
Time = 2.81 (sec) , antiderivative size = 150, normalized size of antiderivative = 1.90 \[ \int \frac {\sec ^2\left (a+b \log \left (c x^n\right )\right )}{x^3} \, dx=\frac {-e^{2 i a} \left (c x^n\right )^{2 i b} \operatorname {Hypergeometric2F1}\left (1,1+\frac {i}{b n},2+\frac {i}{b n},-e^{2 i \left (a+b \log \left (c x^n\right )\right )}\right )+(i+b n) \left (-i \operatorname {Hypergeometric2F1}\left (1,\frac {i}{b n},1+\frac {i}{b n},-e^{2 i \left (a+b \log \left (c x^n\right )\right )}\right )+\tan \left (a+b \log \left (c x^n\right )\right )\right )}{b n (i+b n) x^2} \]
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\[\int \frac {{\sec \left (a +b \ln \left (c \,x^{n}\right )\right )}^{2}}{x^{3}}d x\]
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\[ \int \frac {\sec ^2\left (a+b \log \left (c x^n\right )\right )}{x^3} \, dx=\int { \frac {\sec \left (b \log \left (c x^{n}\right ) + a\right )^{2}}{x^{3}} \,d x } \]
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\[ \int \frac {\sec ^2\left (a+b \log \left (c x^n\right )\right )}{x^3} \, dx=\int \frac {\sec ^{2}{\left (a + b \log {\left (c x^{n} \right )} \right )}}{x^{3}}\, dx \]
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\[ \int \frac {\sec ^2\left (a+b \log \left (c x^n\right )\right )}{x^3} \, dx=\int { \frac {\sec \left (b \log \left (c x^{n}\right ) + a\right )^{2}}{x^{3}} \,d x } \]
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\[ \int \frac {\sec ^2\left (a+b \log \left (c x^n\right )\right )}{x^3} \, dx=\int { \frac {\sec \left (b \log \left (c x^{n}\right ) + a\right )^{2}}{x^{3}} \,d x } \]
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Timed out. \[ \int \frac {\sec ^2\left (a+b \log \left (c x^n\right )\right )}{x^3} \, dx=\int \frac {1}{x^3\,{\cos \left (a+b\,\ln \left (c\,x^n\right )\right )}^2} \,d x \]
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